Hi,

find the vertex, axis of symmetry, and direction of the opening of the parabola 

Putting into vertex form

the vertex form of a parabola opening right or left,  where(h,k) is the vertex.

1. y^2=-8x 

  (-1/8)y^2 = x   Vertex (0,0), a = (-1/8)<0 opens to the left along x-axis

2. (y-8)^2=-4(x-4)

 (1/4)(y-8)^2 +4 = x  Vertex(4,8) a = (-1/4) opens left along y = 8





 

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