SOLUTION: Find the vertex, line of symmetry and the minimum maximum value of f(x) f(x)=1/2(x+8)^2+8 I get vertex (-16x,0) line of symetry -16x, min/max -16 value of f(-8)=8 is minimum grap

SOLUTION: Find the vertex, line of symmetry and the minimum maximum value of f(x) f(x)=1/2(x+8)^2+8 I get vertex (-16x,0) line of symetry -16x, min/max -16 value of f(-8)=8 is minimum grap

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Question 475591: Find the vertex, line of symmetry and the minimum maximum value of f(x)
f(x)=1/2(x+8)^2+8 I get vertex (-16x,0) line of symetry -16x, min/max -16 value of f(-8)=8 is minimum graph points up is this correct?

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Hint: The vertex of is (h,k) and the line of symmetry is x=h. The max/min value is k. Also, k is a min if a > 0 or k is a max if a < 0.
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