SOLUTION: solve the system of equation using substitution. y= 2/3x+1 y= -3/2x+40

Question 468973: solve the system of equation using substitution.
y= 2/3x+1
y= -3/2x+40
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
solve the system of equation using substitution.
y= 2/3x+1
y= -3/2x+40
-----------
Substitute for "y" to get:
(2/3)x+1 = (-3/2)x+40
---
[(2/3)+(3/2)]x = 39
----
[(4+9)/6]x = 39
(13/6)x = 39
----
x = (6/13)39
---
x = 6*3
x = 18
---
Solve for "y":
y = (2/3)x+1
y = (2/3)18 + 1
y = 12+1
y = 13
==============
Cheers,
Stan H.
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