Rule: Ax² + Bx + C = 0 1. Substitute A, B, and C in the discriminant formula Discriminant = B² - 4AC 2. If the discriminant is a positive number then the equation has two real solutions. 3. If the discriminant is a negative number then the equation has two conjugate imaginary solutions. 4. If the discriminant is zero then the equation has one real solution. ---------------------------------------------- x² - 4x - 5 = 0 A = 1, B = -4, C = -5 Substitute A=1, B=-4, and C=-5 in the discriminant formula Discriminant = B² - 4AC Discriminant = (-4)² - 4(1)(-5) Discriminant = 16 + 20 Discriminant = 36 36 is a negative number, so the equation has two real solutions. ----------------------------- x² - 12x + 36 = 0 A = 1, B = -12, C = 36 Substitute A=1, B=-12, and C=36 in the discriminant formula Discriminant = B² - 4AC Discriminant = (-12)² - 4(1)(36) Discriminant = 144 - 144 Discriminant = 0 That came out zero, so the equation has one real solutions. Edwin