Hi,

Find all rational roots of the equation 

 x^3-5x^2-4x+20=0   |If x = 2  then 8-20-8-20= 0

 x^3-5x^2-4x+20)/(x-2) = x^2-3x-10

 (x-2)(x^2-3x-10) = 0

            

            

              x = (3 ± 7)/2   x = 5 and x = -2

 Rational roots are: -2,2,5 

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