SOLUTION: Given that (3x-a)(x-2)(x-7) = 3x^3-32x^2=81x-70, determine the value of a. My answer came out to be 3, but not sure of my answer. thanks for looking over my answer.

Question 43923This question is from textbook Algebra and Trigonometry with Analytic Geometey
: Given that (3x-a)(x-2)(x-7) = 3x^3-32x^2=81x-70, determine the value of a. My answer came out to be 3, but not sure of my answer. thanks for looking over my answer. This question is from textbook Algebra and Trigonometry with Analytic Geometey

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given that (3x-a)(x-2)(x-7) = 3x^3-32x^2=81x-70, determine the value of a.
(3x-a)(x^2-9x+14)
3x^3-27x^2+42x-ax^2+9ax-14a
3x^3-(27+a)x^2+(42+9a)x-14a=3x^3-32x^2+81x-70
This says:
-27-a=-32 or a=5
and
42+9a=81 or a=39/9
and -14a=-70 or a=5
There is a contradiction here that I think is the result of your posting.
Please check your posting.
Cheers,
Stan H.
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