# SOLUTION: I just asked a question but was slightly wrong,here is the correct wording: If f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x) is greater than 0. The la

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: I just asked a question but was slightly wrong,here is the correct wording: If f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x) is greater than 0. The la      Log On

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 Question 43896: I just asked a question but was slightly wrong,here is the correct wording: If f(x)=x(x+3)(x-1), use interval notation to give all values of x where f(x) is greater than 0. The last email said less than 0,I typed it wrong. ThanxAnswer by fractalier(2101)   (Show Source): You can put this solution on YOUR website!A good way to analyze f(x) = x(x+3)(x-1) is to set up a number line and plot open points where f(x) equals zero, that is, at x = 0, x = -3, and at x = 1. Open because the requirement is not "or equal to." Then you test points within each interval (there are four of them) to see if f(x) becomes positive...try x = 2 for example...it works...thus part of the solution is x > 1. Then try x = 1/2. It doesn't work. Then try x = -1. That works, so that -3 < x < 0. Then try x = -5. That doesn't work... And that is how you analyze this type of problem... Our solution is x > 1 or -3 < x < 0.