SOLUTION: Find the center and radius of the circle
x^2+y^2-18x+4y+4=0
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Question 426851: Find the center and radius of the circle
x^2+y^2-18x+4y+4=0
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
^2\ +\ (y\ -\ k)^2\ =\ r^2)
is the equation of a circle with center at )
and radius 
Move the constant to the RHS
Divide the coefficient on the first degree 
term by 2 and square the result. Add that result to both sides, completing the square in . Do the same thing with the coefficient on the first degree 
term.
Collect terms in the RHS and factor the two perfect square trinomials in the LHS.
^2\ +\ (y\ +\ 2)^2\ =\ 81)
Finally, rewrite your equation thus:
^2\ +\ \left(y\ -\ (-2)\right)^2\ =\ 9^2)
Now you can determine the center and radius by inspection. Compare to the pattern given at the beginning.
John
My calculator said it, I believe it, that settles it
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