SOLUTION: f(x)=(2x-4)/(x^2-6x-16): What is the vertical asymptote, horizontal asymptote, x-intercept, and y-intercept? Could anyone explain how to do this kind of problem to me as well? I

Question 426804: f(x)=(2x-4)/(x^2-6x-16): What is the vertical asymptote, horizontal asymptote, x-intercept, and y-intercept?
Could anyone explain how to do this kind of problem to me as well? I have a test tomorrow!
Answer by htmentor(1343) (Show Source): You can put this solution on YOUR website!
We can factor the function as:

We see immediately from this that there are 2 vertical asymptotes: x=-2, x=8, since f(x) -> at these points
For large x, the function goes as
This approaches, but never reaches 0, so the horiz. asymptote is: f(x)=0
x-intercept is when f(x)=0 -> 2(x-2) = 0 -> x=2
y-intercept: x=0 -> (0-2)/(-16), or x=1/8
This is the graph

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