Hi

what are the zeros in 

 3x^4+4x^3-21x^2-10x+24     |If x = 1 then 3+4-21+24 = 0

dividing the above by (x-1)results in:

 3x^3+7x^2-14x-24             |If x = 2 then 24+28-28-24 = 0

dividing the above by (x-2)results in:

 3x^2 + 13x +12

factoring

 (3x+4)(x+3)=0

 (3x+4)= 0  x = -4/3

  (x+3)=0   x = -3

the 4 'zeros' for x are: -3,-4/3,1,2 

RELATED QUESTIONS

what are the positive zeros of... (answered by Alan3354,KMST)

State the possible Zeros 
1. x^3-3x^2-10x+24
2. 2x^3-5x^2-28x+15

Find all zeros 
1.  (answered by Seutip)

What are all the real zeros of... (answered by MathLover1)

how to find all the zeros for 
4x^5+12x^4-41x^3-99x^2+10x+24
 (answered by Alan3354)

What is the upper limit for the zeros of the function 
P(x) = 4x^4 + 8x^3 - 7x^2 - 21x -  (answered by stanbon)

(21x² - 10x + 5 ) / ( 4x – 2... (answered by fractalier)

Factor each expression completely.

1. -3x^2+21x

2. x^2-16

3. x^2-10x+24

4.... (answered by MathLover1)

Show that the given values of c are zeros of P(x), and find all other zeros of P(X)... (answered by ReadingBoosters)

Sloving Equations With Variables On Both Sides
9x+24=-3x solution
8-9x=21x-17... (answered by jessica ibekwe)