# SOLUTION: Use the Intermediate Value Theorem to show that the graph of the function has a zero in the given interval. Round the zero to two decimal places. f(x) = 2x3 + x2 – x – 5; [1, 2

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: Use the Intermediate Value Theorem to show that the graph of the function has a zero in the given interval. Round the zero to two decimal places. f(x) = 2x3 + x2 – x – 5; [1, 2      Log On

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 Algebra: Rational Functions, analyzing and graphing Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Rational-functions Question 41619: Use the Intermediate Value Theorem to show that the graph of the function has a zero in the given interval. Round the zero to two decimal places. f(x) = 2x3 + x2 – x – 5; [1, 2] Please helpAnswer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!Use the Intermediate Value Theorem to show that the graph of the function has a zero in the given interval. Round the zero to two decimal places. f(x) = 2x3 + x2 – x – 5; [1, 2] Please help F(1)=2+1-1-5=-3 F(2)=2*2^3+2^2-2-5=16+4-2-5=13 F(X) IS CONTINUOUS IN THIS RANGE AND CHANGES ITS SIGN FROM -VE TO +VE.HENCE IT HAS ZERO IN THIS RANGE NARROWING THE RANGE TO GET AT THE ZERO..TRY X=(1+2)/2=1.5 F(1.5)=2.5.. THEN...TRY...(1+1.5)/2=1.25 ..F(1.25)=-0.78 THEN ..TRY....(1.25+1.5)/2=1.375....F(1.375)=0.714.......ETC.. WE FIND BY TRIAL THAT AT X=1.32 F(X)=0