SOLUTION:

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Question 412605:
Answer by bsmath(21) About Me  (Show Source):
You can put this solution on YOUR website!
5x+4y=-30 3x-9y=-18
The second equation can be divided by three: 3x/3-(9/3)y=(-18)/3
x-3y=-6 Now solve for x: x=3y-6 Substitute in the first equation:
5(3y-6)+4y=-30 15y-30+4y=-30 19y-30=-30 19y=0 y=0 Substitue y=0
5x-4(0)=-30 5x=-30 x=-6 Check by plugging in y-0 x=-6 in the second equation:
3(-6)-9(0)=-18