SOLUTION: {{h(x)=2^x}} or {{{ln(h(x)) = x*ln(2)}}} or {{{x = ln(h(x))/ln(2)}}} = log(h(x)) to the base 2
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-> SOLUTION: {{h(x)=2^x}} or {{{ln(h(x)) = x*ln(2)}}} or {{{x = ln(h(x))/ln(2)}}} = log(h(x)) to the base 2
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Question 40854
:
{{h(x)=2^x}}
or
or
= log(h(x)) to the base 2
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psbhowmick(878)
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