SOLUTION: solve (4x+3)^2/3=(16x+44)^1/3

Question 398302: solve (4x+3)^2/3=(16x+44)^1/3
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
solve (4x+3)^2/3=(16x+44)^1/3
...
take the cube on both sides
(4x+3)^2=(16x+44)
16x^2+24x+9=16x+44
16x^2+24x-16x+9-44=0
16x^2+8x-35=0
Find the roots of the equation by quadratic formula
a= 16 , b =8 , c = -35
b^2-4ac= 2304 .

x1= 1.25

x2=-1.75
...
m.ananth@hotmail.ca

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