SOLUTION: Please help me determine an equation of the line through (-3,4) and perpendicular to the line with the equation 4x-2y=1. I came up with y=-2x+7. Am I even close?

Question 39145: Please help me determine an equation of the line through (-3,4) and perpendicular to the line with the equation 4x-2y=1. I came up with y=-2x+7.
Am I even close?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
determine an equation of the line through (-3,4) and perpendicular to the line with the equation 4x-2y=1.
Determine the slope of the line you want.
4x-2y=1
2y=4x-1
y=2x-(1/2)
The slope of the given line is m=2
Therefore the slope of the line perpendicular
to it is m=-1/2
The form of the line you want is y=mx+b
You have x=-3, y=4, and m=-1/2
So, 4=(-1/2)(-3)+b
b=4-3/2= 5/2
The equation of your line is y=(-1/2)x+5/2
Cheers,
Stan h.

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