SOLUTION: Let function(x)be definedas f(x) =xx+bx+c, where bandc are real numbers
determine all pairs(b,c)such that /f(x)/ is less than equal to 8for all x in the interval. /1,9/
Algebra ->
Rational-functions
-> SOLUTION: Let function(x)be definedas f(x) =xx+bx+c, where bandc are real numbers
determine all pairs(b,c)such that /f(x)/ is less than equal to 8for all x in the interval. /1,9/
Log On
values at the border : y1=b+c+1, y2=81+9b+c
minimum at -b/2 value : ym=-b^2/4+c
|f(x)| is <=8 if all three value are
hence the conditions are : |b+c+1|<=8 |81+9b+c|<=8
if 1<-b/2<9 which is the same as : -2>b>-18, there should |-b^2/4+c|<8
hence the solution if :
{ (b,c) | |b+c+1|<=8 and |81+9b+c|<=8 and (|b^2/4-c|<=8 if b in [-18,-2]) }