SOLUTION: a. The point on the x-axis that is equidistant (equal distance) from (8,4) and (-4,2)
b. The distance between the points (8,2) and (16,2). 8
c. The distance between the points
Algebra.Com
Question 387349: a. The point on the x-axis that is equidistant (equal distance) from (8,4) and (-4,2)
b. The distance between the points (8,2) and (16,2). 8
c. The distance between the points (2,6) and (12,8).2
d. The midpoint between (8,2) and (10,6).
e. The midpoint between (-4, 2) and (-5, 3).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
a. The point on the x-axis that is equidistant (equal distance) from (8,4) and (-4,2)
The point will be (x,0)
Use d squared, since it will be equal if d is =
76 - 16x = 16 + 8x
60 = 24x
x = 2.5
---> (2.5,0)
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b. The distance between the points (8,2) and (16,2). 8
8 is right.
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c. The distance between the points (2,6) and (12,8).2
How did you get 2?
d=~ 10.198 units
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d. The midpoint between (8,2) and (10,6)
Find the average of x and y separately
x: (8 + 10)/2 = 0
y: (2 + 6)/2 = 4
--> (0,4)
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e. The midpoint between (-4, 2) and (-5, 3)
Same method as d --> (-4.5,2.5)
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