SOLUTION: Which of the following is the correct solution to the equation x^2-4x+6=0? Explain why the other solutions are wrong. a) Solution 1 x = 4±(√4^2-4•1•6)/2 x = 4±√-8/2

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Question 383332: Which of the following is the correct solution to the equation x^2-4x+6=0? Explain why the other solutions are wrong.
a) Solution 1
x = 4±(√4^2-4•1•6)/2
x = 4±√-8/2
x = 2±√-4
x = 2±2i
b) Solution 2
x = 4±(√4^2-4•1•6)/2
x = 4±√-8/2
x = 2±√-8
x = 2±2i√2
c) Solution 3
x = 4±(√4^2-4•1•6)/2
x = 4±√-8/2
x = 4±2i√2/2
x = 2±2i√2
Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

The discriminant -8 is less than zero. That means that there are no solutions among real numbers.

If you are a student of advanced school algebra and are aware about imaginary numbers, read on.


In the field of imaginary numbers, the square root of -8 is + or - .

The solution is , or
Here's your graph:

----------
x = 2 ± i*sqrt(2)
------------------
They're wrong because they're not the correct answers.
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