SOLUTION: 1. Let the function h be defined by h(x)=14+x^2/4; If h(2m)=9m, what is one possible value of m? 2. If the function f is defined by f(x)=x-4/2, for what value of x does f(x)=30?

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Question 379027: 1. Let the function h be defined by h(x)=14+x^2/4; If h(2m)=9m, what is one possible value of m?
2. If the function f is defined by f(x)=x-4/2, for what value of x does f(x)=30?
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
1. Let the function h be defined by
h(x)=14+x^2/4;
If h(2m)=9m,
what is one possible value of m?
----
h(2m) = 14+ (2m)^2/4
h(2m) = 9m
-----------------------
Equation:
9m = 14 + (4m^2)/4
---
9m = 14 + m^2
m^2 - 9m + 14 = 0
(m-7)(m-2) = 0
m = 7 or m = 2
===========================

2. If the function f is defined by f(x)=x-4/2, for what value of x does f(x)=30?
Solve: (x-4)/2 = 30
x-4 = 60
x = 64
====================
Cheers,
Stan H.
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!


Hi,





9m = 14 + 4m^2/4

m^2 -9m + 14 = 0

(m-7)(m-2) = 0 Note:SUM of the inner product(-7m) and the outer product(-2m)= -9m

(m-7)= 0

m = 7

(m-2) = 0

m = 2



f(x)=x-4/2

f(x)=30

30 = x - 2

32 = x 

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