SOLUTION: 3(2x+3/3x-8)-8 over 4(2x+3/3x-8)-1
I got to 9x-32/12x-33 I'm not sure if this is right or how to continue
Algebra.Com
Question 377601: 3(2x+3/3x-8)-8 over 4(2x+3/3x-8)-1
I got to 9x-32/12x-33 I'm not sure if this is right or how to continue
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
3(2x+3/3x-8)-8 / 4(2x+3/3x-8)-1
Numerator:
((6x+9)/(3x-8))-(8(3x-8)/(3x-8))
=(6x+9-24x+64)/(3x-8)
=(-18x+73)/(3x-8)
Denominator:
(8x+24)/(3x-8) - (3x-8)/(3x-8)
=(8x+24-3x+8)/(3x-8)
=(5x+32)/(3x-8)
.
(-18x+73)/(3x-8) / (5x+32)/(3x-8)
=(-18x+73)/(3x-8) * (3x-8)/(5x+32)
=(-18x+73)/(5x+32)
.
Ed
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