# SOLUTION: s^2+6s+25= solve for Solution sets 2x^2-9x=1 solve for x Can you show me how you find the answer, not just the answer?

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 Question 37567: s^2+6s+25= solve for Solution sets 2x^2-9x=1 solve for x Can you show me how you find the answer, not just the answer?Answer by junior403(76)   (Show Source): You can put this solution on YOUR website!s^2+6s+25= solve for Solution sets The s^2 indicates there will be 2 solutions. Besure that the quadratic equation is equal to zero. Use quadratic formula to solve. In this case... s^2+6s+25=0 ax^2+bx+c=0 plug in your variables a=1 b=6 c=25 So... and... and... The negative number beneith the radical will result in an imaginary expression. Thus... So... or... Remember, first factor out the 2 in the numerator and then cancel... and... So the solution set is... {-3+4i,-3-4i} So for the equation... 2x^2-9x=1 Use the same process first making equation equal to zero. So... 2x^2-9x=1 (subtract 1 from both sides of the equation then begin) 2x^2-9x-1=0 Again x^2 indicates 2 solutions Use quadratic formula by plugging in indicated variables a=2 b=-9 c=-1 (remember -b means the OPPOSITE of the value of b) So... Then... And... 89 is aprime number so there is no square root. So you final result is the solution set... ,