To make things easier for me I am going to replace the Greek letters as follows:
x = Δ
y = Ο
z = Ω
This makes your expression
(x + y)/(z/x/z)
The solution to the problem depends on what
z/x/z
means.
If z/x/z means ...
I will start by mutiplying the numerator and denominator of the "big" fraction by x/z:
In the denominator of the "big" fraction the (x/z)'s cancel:
So now we have:
Next I'll multiply the numerator and denominator of the "big" fraction by z:
In the numerator the z's cancel:
leaving
Using the Distributive Property in the numerator we get:
which is answer b.
If z/x/z means ...
This time I'll start by multiplying the numerator and denominator of the "big" fraction by z:
The z's in the denominator cancel:
leaving
Next I'll multiply the numerator and denominator of the "big" fraction by x:
The x's in the denominator cancel:
leaving:
Now the z's cancel:
leaving
or
which does not fit any of the answers given. So apparently
z/x/z
means
In the future, please write such a fraction as
z/(x/z)
so the problem is clear. Tutors are more likely to help when the problems are clearly stated.
P.S. In response to the comments your "Thank you".
1) If the problem your instructor gave you provided no information as to whether the expression was
x+y
_________
z
_______
x
___
z
or
x+y
_________
z
___
x
_______
z
These two are NOT the same. And if there were no clues as to which one of the above is correct, then the problem was not defined properly. A problem should be unambiguous. My "remark at the end" was just a request for an unambiguous expression.
2) If my solution "didn't help", then you're not trying very hard. My solution, using basic properties of Algebra, shows why (b) is the correct answer. This was the hard part. I even showed you how I determined which interpretation of (Δ+Ο)/(Ω/Δ/Ω) was the correct one to use. The only thing missing is the brief explanation as to why the others are wrong. For this, all you need to say is that the original expression cannot be transformed into either of the other two using the properties of Algebra.
3) If you're going to be critical of the free help you are getting, then
a) know what you're talking about. The expression you posted was ambiguous. Either it was given to you as ambiguous or you overlooked something that would have made the correct expression clear. Either way, my "remark at the end" is totally correct and reasonable.
b) you should "do it right", too. Look up the difference between "your" and "you're".