Hi, 

Note: x^2 + 2x -3 = (x+3)(x-1)

2/x-1 - x/x+3 = 6/x^2+2x-3

note: x = 1 cannot be a solution as it would result in a denominator  = 0

Multiplying each term on both sides of the equation by (x+3)(x-1)so as all denominators = 1



2(x+3) - x(x-1) = 6

solving for x

2x + 6 - x^2 + x = 6

x + 6 -x^2 = 6

0 = x^2 - x

0 = x(x-1)

x = 0

x = 1 See above, this is not a solution 

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