SOLUTION: Problem 1: (√x+4) +2 = (√x + 20)
I know the answer is 5, but do not understand how to work the problem.
Problem 2: (5√x-2) -3 = (√19x-29)
How do you
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Question 348136: Problem 1: (√x+4) +2 = (√x + 20)
I know the answer is 5, but do not understand how to work the problem.
Problem 2: (5√x-2) -3 = (√19x-29)
How do you get 27 as the answer?
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Problem 1: (√x+4) +2 = (√(x + 20))
I know the answer is 5, but do not understand how to work the problem.
---
Square both sides to get:
(x+4) + 4(sqrt(x+4)) + 4 = x + 20
------
4sqrt(x+4) = 12
sqrt(x+4) = 3
----
Square both sides to get:
x+4 = 9
x = 5
===============
Problem 2: (5√x-2) -3 = (√19x-29)
Square both sides to get:
25(x-2) - 6*5sqrt(x-2) + 9 = 19x-29
----
25x-50 - 30sqrt(x-2) = 19x-38
-30sqrt(x-2) = 12-6x
------------------------
(5√x-2) -3 = (√19x-29)
---
x cannot be 2
----
Final Answer: x = 27
==========================
Cheers,
Stan H.
-5sqrt(x-2) = 2-x
----
Square both sides:
25(x-2) = 4 - 4x + x^2
25x-50 = 4 - 4x + x^2
x^2 -29x+54 = 0
(x-27)(x-2) = 0
---
x = 27 or x = 2
------------------------
Checking in original equation:
How do you get 27 as the answer?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
If I am understanding your question properly:
.
SQUARE BOTH SIDES OF THE EQUATION:
.
squaring left side gives:
.
squaring right gives (x+20)
.
Result of squaring both sides of the equation:
.
Simplifying
.
SQUARING BOTH SIDES OF THIS EQUATION
x+4 = 9
x=5
.
this is solved as above: fist Squaring both sides of the equation, simplifying and once again squaring both sides of the equation to solve for x
Square both sides to get:
.
SQUARE BOTH SIDES
.
factor
x=27 or x=2
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