SOLUTION: please factor completely
4c^2+9-12c
What do I do first?
Algebra.Com
Question 346178: please factor completely
4c^2+9-12c
What do I do first?
Found 3 solutions by Fombitz, rfer, ewatrrr:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Oops!
You're correct that is the answer.
Sorry for screwing you up there.
(2c-3)(2c-3)=4c^2-6c-6c+9=4c^2-12c+9
I will correct it on the website too.
I could say I was just testing you but I just screwed up.
Good work!
Answer by rfer(16322) (Show Source): You can put this solution on YOUR website!
4c^2-12c+9
(2c- 3)(2c- 3)
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
Hi,
.
First put in this form:
.
Check for factoring: *Hint: First Ask Yourself: What numbers added together have a sum of -12 (-6 and -6)
.
Then:
What two numbers have a product of 4 and what two numbers have a product of 9 such that the product of these numbers will be -6
.
.
Check you answer:
=
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