SOLUTION: What is the vertex form of: f(x)=x^2-2x-5

Question 340383: What is the vertex form of:
f(x)=x^2-2x-5
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Vertex Form: y = a(x-h)^2+k where (h,k) is the vertex.
What is the vertex form of:
f(x)=x^2-2x-5
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y+5 = x^2-2x
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Complete the square on the x-terms:
y+5 + 1 = x^2-2x+1
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Simplify the left and factor the right side to get:
y + 6 = (x-1)^2
y = (x-1)^2-6
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Vertex at (1,-6)
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Graph:

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Cheers,
Stan H.
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