SOLUTION: Solve the following equation. (x+7)/(x^(2)-25)-(1)/(x-5)=x^(2)-4)/(x^(2)-25)

Algebra.Com
Question 325272: Solve the following equation.
(x+7)/(x^(2)-25)-(1)/(x-5)=x^(2)-4)/(x^(2)-25)

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given equation.


Factor to get


Multiply every term by the LCD to clear out the fractions.


Distribute.


Get every term to the left side.


Rearrange the terms.


Multiply every term by -1 to make the leading coefficient positive.


Notice that the quadratic is in the form of where , , and


Let's use the quadratic formula to solve for "x":


Start with the quadratic formula


Plug in , , and


Square to get .


Multiply to get


Rewrite as


Add to to get


Multiply and to get .


Simplify the square root (note: If you need help with simplifying square roots, check out this solver)


Break up the fraction.


Reduce.


or Break up the expression.


So the solutions are or

RELATED QUESTIONS

3 / x^2 - 25 = 1 / x + 5 + 2 / x - 5 Solve the equation for the... (answered by mananth)
Solve the following exponential equation (1)5^2x-26(5^x)+25=0 (2)2^2x+2^x+1-8=0... (answered by solver91311,ikleyn,Boreal)
Solve equation... x+7=10 x+14=25 x-2= -4 3+x= -11... (answered by ewatrrr)
solve... (answered by praseenakos@yahoo.com)
solve... (answered by praseenakos@yahoo.com)
Please help me solve the following equation. {{{ sqrt( x^2-25 )=x+5 }}} (answered by vleith)
(2/5)^x =... (answered by Edwin McCravy)
Solve for x in the following. A) 3^x=27 B) 16^x=64 C) 2=(1/32)^x D)... (answered by MathLover1)
x-5/x^2-25 (answered by checkley77)