SOLUTION: (7z+5)^2+2(7z+5)-15=0

Question 318135: (7z+5)^2+2(7z+5)-15=0
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
(7z+5)^2+2(7z+5)-15=0
let (7z+5)be =x
x^2+2x-15=0
x^2+5x-3x-15=0
x(x+5)-3(x+5)=0
(x-3)(x+5)=0
replace the value of x
(7z+5-3)(7z+5+5)=0
(7z+2)(7z+10)=0
z=-2/7 or z=-10/7
RELATED QUESTIONS
-6z^2+7z+3=0 (answered by jim_thompson5910)

7z^6/10z^5 (answered by jim_thompson5910)

7z+3<6z-5 (answered by mananth)