SOLUTION: Hi again,
I have an equation with a radical inside a radical inside a radical equal to another radical (I'm writing it in exponential form):
(1+(x+(2x+1)^1/2)^1/2)^1/2 = (5+(x)^1
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Question 31390This question is from textbook College Algebra
: Hi again,
I have an equation with a radical inside a radical inside a radical equal to another radical (I'm writing it in exponential form):
(1+(x+(2x+1)^1/2)^1/2)^1/2 = (5+(x)^1/2)^1/2
I tried to square both sides but got lost on the right side after squaring boths sides for the second time coming out with x-3=-x^1/2 after squaring the third time to remove the -x^1/2 remaining on the left side.
Does this equation actually have solutions?
Thank you for all your wonderful help!
This question is from textbook College Algebra
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
Hi again,
I have an equation with a radical inside a radical inside a radical equal to another radical (I'm writing it in exponential form):
(1+(x+(2x+1)^1/2)^1/2)^1/2 = (5+(x)^1/2)^1/2
IF THIS EQN. MEANS THIS WAY THEN IT HAS A SOLUTION........
(2X+1)^1/2 MEANS ((2X+1)^1)/2=(2X+1)/2...LIKE WISE ALL OTHER TERMS TOO....
THEN THE ANSWER IS X=7.5
IF IT MEANS AS YOU IMPLIED
(2X+1)^0.5...THEN THE ANSWER IS X TENDS TO INFINITY.
I tried to square both sides but got lost on the right side after squaring boths sides for the second time coming out with x-3=-x^1/2 after squaring the third time to remove the -x^1/2 remaining on the left side.
Does this equation actually have solutions?
Thank you for all your wonderful help!
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