SOLUTION: Find the zeros of the function by factoring or algebraically: {{{ (x^3-36x) /(x+3)^2 }}} please note the x^3 was meant to be atop the fraction with the 36x so it should be x^

Algebra ->  Rational-functions -> SOLUTION: Find the zeros of the function by factoring or algebraically: {{{ (x^3-36x) /(x+3)^2 }}} please note the x^3 was meant to be atop the fraction with the 36x so it should be x^      Log On


   

Question 310411: Find the zeros of the function by factoring or algebraically:
+%28x%5E3-36x%29+%2F%28x%2B3%29%5E2+
please note the x^3 was meant to be atop the fraction with the 36x so it should be x^3-36x atop the fraction.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

Factor the numerator:



Then set the function equal to zero and multiply by the denominator:



Hence,



or



or



Note: I put parentheses around your numerator so that the equation editor what parts go together.


John