SOLUTION: determine all asymptotes(vertical,horizonalor oblique) f(x)= 2^2-3x+2/4x^2-1

SOLUTION: determine all asymptotes(vertical,horizonalor oblique) f(x)= 2^2-3x+2/4x^2-1

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Question 294585: determine all asymptotes(vertical,horizonalor oblique)
f(x)= 2^2-3x+2/4x^2-1
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Vertical asymptotes occur when the denominator goes to zero.

and
The vertical asymptotes are shown below in blue.
.
.
.
Horizontal asymptotes occur as x goes to infinity.
Divide numerator and denominator by .

Now as x goes to infinity,

the crossed out terms go to zero.

The horizontal asymptote would be y=1/2 (shown below in green).
There are no oblique asymptotes.
.
.
.

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