You can
put this solution on YOUR website!The correct problem should be something like this:
{[(x^2-2x-3)/(x+1)]divided by [(x^2+x-12)/(x^2)]}-1
{[(x^2-2x-3)/(x+1)]divided by [(x^2+x-12)/(x^2)]}-1
= {[(x-3)(x+1)/(x+1)]divided by [(x+4)(x-3)/(x^2)]}-1
={[(x-3)]divided by [(x+4)(x-3)/(x^2)]}-1 (cancelling (x+1)
={[(x-3)]mulitplied by[(x^2)/(x+4)(x-3)]}-1
(if the division sign is changed into multiplication symbol then then the fraction after the division sign is reciprocated)
={[(x-3)]X[(x^2)/(x+4)(x-3)]}-1
={[(x-3)(x^2)/(x+4)(x-3)]}-1
=[(x^2)/(x+4)]-1 (cancelling (x-3)
=[(x^2)-1(x+4)]/(x+4)
= (x^2-x-4)/(x+4)
You can
put this solution on YOUR website!First off, being picky, this is not an equation, since there is no equals sign. All you can do is just simplify the expression, so that is what i shall do :-)
I am assuming a few things, as i am not sure, from your question:
1. the final -1 is not a power
2. the final -1 is on the denominator
3. as you have written it, the equation is still dubiously written as it looks like
I am assuming it should be:

, in which case:
jon.