# SOLUTION: This is a two-part problem. For {{{ f(x) = sqrt ( 1-2x ) }}} {{{ g(x) = -x+3 }}} A) Find (FºG)(x) B) Find the domain of (FºG)(x) What I have so far, which I am not to

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: This is a two-part problem. For {{{ f(x) = sqrt ( 1-2x ) }}} {{{ g(x) = -x+3 }}} A) Find (FºG)(x) B) Find the domain of (FºG)(x) What I have so far, which I am not to      Log On

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 Question 287328: This is a two-part problem. For A) Find (FºG)(x) B) Find the domain of (FºG)(x) What I have so far, which I am not totally sure about it: (FºG)(x) = simplified into Is that correct for step A)? And how do I find the domain for step B)?Answer by jsmallt9(3296)   (Show Source): You can put this solution on YOUR website!You did part A exactly right! For the domain, you just have to find the set of acceptable values for x. The function you found in part A has the x inside a square root. Since we must have a non-negative (zero or positive) number inside the square root, the only values we can allow x to be are those those that make 2x-5 non-negative. In other "words" Solving this: This describes the acceptable values of x. This is the domain.