SOLUTION: Find all the zeros of the function: p(x)=X^3-2x^2+9x-18

Question 286276: Find all the zeros of the function:
p(x)=X^3-2x^2+9x-18
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find all the zeros of the function:
p(x)=X^3-2x^2+9x-18
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I graphed it and found it has a zero at x = 2
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Use synthetic division to find the quotient:
2)...1....-2....9....-18
.....1.....0....9....|..0
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Quotient: x^2 +9
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Factor the quotient:
(x+3i)(x-3i) = 0
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Zeroes: 2 or -3i or +3i
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Cheers,
Stan H.
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