SOLUTION: I need to reduce to lowest terms
3x (numerator)
(x^2-5x) denominator
I think that it is already to lowest terms because I can't seem to get an answer.
Algebra.Com
Question 28100: I need to reduce to lowest terms
3x (numerator)
(x^2-5x) denominator
I think that it is already to lowest terms because I can't seem to get an answer.
Answer by sdmmadam@yahoo.com(530) (Show Source): You can put this solution on YOUR website!
3x (numerator)
(x^2-5x) denominator
(3x)/(x^2-5x)
=3x/x(x-5) (observe that x is found each of the two terms in the dr)
=3/(x-5) (cancelling x in the nr and in the dr )
Answer:3/(x-5)
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