SOLUTION: if y varies directly as x and inversely as z^2, and y=3 when x=2 and z=4. what is the value of x when y=6 and z=2. i dont get this at all please help.

Question 280075: if y varies directly as x and inversely as z^2, and y=3 when x=2 and z=4. what is the value of x when y=6 and z=2. i dont get this at all please help.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
if y varies directly as x and inversely as z^2, and y=3 when x=2 and z=4. what is the value of x when y=6 and z=2. i dont get this at all please help.
---------------
y = kx/z^2
Solve for "k" if y = 3 when x = 2 and z = 4:
---
3 = k*2/4^2
k = 24
------------
Equation:
y = 24x/z^2
------------------
Find "x" when y = 6 and z = 2:
6 = 24*x/4
x = 1
====================
Cheers,
Stan H.
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