SOLUTION: Graph:
f(x) = -2x, x<=-2
f(x) = -3,-2<x<=1
f(x) = 4x-6, x>1
On these types of problems I am used to being given an x-substitute, for example, graph problem one whe
Algebra.Com
Question 277792: Graph:
f(x) = -2x, x<=-2
f(x) = -3,-2
f(x) = 4x-6, x>1
On these types of problems I am used to being given an x-substitute, for example, graph problem one when x = 2, I would then sub in the number and solve. I am perplexed about how to do this without a substitute.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The second question was also messed up, it should have been
-3, when -2 < x <= 1
The way the problem is shown to me is
f(x) = {
and the three equations come within the single { which stretches to encompass all of them.
Graph:
f(x) = -2x, x<=-2
f(x) = -3, -2
f(x) = 4x-6, x>1
---------------------
So this is the graph of a semented function.
On the x-interval (-inf,-2] graph the line y = -2x
On the x-interval (-2,1} graph the line y = -3
On the x-interval (1,+inf) graph the line y = 4x-6
----------------------------------------------------------
To do each of these you need to determine two points
that are on each interval.
For example, on the (-inf,-2) interval you could have
(-5,10) and (-2,4)
Draw a line segment thru those points ending at (-2,4).
---
On the next interval you have points (-2,-3) and (1,-3)
Draw a line sement connecting those points.
------------------------
On the last interval you have points (1,-2) and arbitrary (4,10)
Draw a line segment that starts at (1,-2) and passes thru (4,10)
-----------------------------------------------------
Those three line segments comprise the graph of f(x)
======================================================
Cheers,
Stan H.
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