SOLUTION: Solve the equation 3x^3+7x^2-22x-8=0 given that (-1/3) is a root

Question 269872: Solve the equation 3x^3+7x^2-22x-8=0 given that (-1/3) is a root
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
We can use synthetic division. It is easier than polynomial.
(-1/3)// . . . . . . 3 . . . . . . 7 . . . . . . . -22 . . . . . . . .-8
. . . . . . . . . . . . . . . . . . . .-1. . . . . . . .-2. . . . . . . . 8
. . . . . . . . . . . . .3. . . . . . .6 . . . . . . . .-24 . . . . . . . .0
we now must factor 3x^2 + 6x - 24 as (3x - 6)(x + 4)
set this equal to zero and we get
x = 2
or
x = -4
-----
So our roots are: {-4, -1/3, 2)
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