SOLUTION: Hi :o)
Last calculus question if anyone can help???
Find derivative of y = (x-1)³(x²-2)²
I thought I'd need to use both the product and chain rules, so tried;
u=(x-1)³ d
Algebra.Com
Question 260676: Hi :o)
Last calculus question if anyone can help???
Find derivative of y = (x-1)³(x²-2)²
I thought I'd need to use both the product and chain rules, so tried;
u=(x-1)³ du^n/dx=3(x-1)²(1)
v=(x²-2)² dv^n/dx=2(x²-2)^1(2x)
= {(x-1)³[3(x-1)²(1)]} + {(x²-2)²[2(x²-2)^1(2x)]}
= [(x-1)³3(x-1)²] + [(x²-2)²4x(x²-2)]
= 3(x-1)^5 + 4x(x²-2)^3
...does that look right? Can I go further?
Thanks so, so much again :o)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
^3(x^2-2)^2)
... Start with the given equation
^3(x^2-2)^2\right))
... Derive both sides with respect to x.
^3\right)(x^2-2)^2+(x-1)^3\frac{d}{dx}\left((x^2-2)^2\right))
... Use the product rule.
^2(x^2-2)^2+4x(x-1)^3(x^2-2))
... Use the chain rule.
Here's confirmation of the answer.
RELATED QUESTIONS
I need to find the derivative of these two questions. Can you please help me?
y=... (answered by Alan3354)
There is no section for calculus but I really need some help
find the second... (answered by Alan3354)
I need to graph y=(1/2)^x-3 +1
I also need to find the intercepts. Can anyone... (answered by Nate)
Calculus Derivatives
I need to find the derivative of
y = 4 cot^3... (answered by Fombitz)
Find the equation of line with a slope -1 that is the tangent to the curve y=1/x-1... (answered by AnlytcPhil)
sort of a calculus question... Find the derivative of the inverse function (f^-1)'(a) if... (answered by Theo)
Sorry this is calculus but I thought I would take a stab at it anyway.
A rectangle is... (answered by richard1234)
Sorry I can’t find calculus topic so I’ll ask here instead, am I able to find the... (answered by MathLover1,ikleyn)
If y = tan^-1(x/a)
So y'=a/(x^2+a^2) [by differentiating]
Y'=a/(x-ia)(x+ia) why... (answered by Fombitz)