SOLUTION: Please help me!! And can you please show me how you did it?!?! Find the horizontal asymptote of f(x)=1/(x^2-16)

Question 255949: Please help me!! And can you please show me how you did it?!?!
Find the horizontal asymptote of f(x)=1/(x^2-16)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please help me!! And can you please show me how you did it?!?!
Find the horizontal asymptote of f(x)=1/(x^2-16)
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1st: find the highest power of the variable.
It may be in the numerator or in the denominator.
---
In your problem that is is x^2
----
The numerator of your problem has zero x^2
The denominator of your problem has one x^2
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2nd: The horizontal asymptote is y = 0/1 or y = 0
===================================================
If you graph your problem you will see that the
horizontal asymptote is y = 0

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Cheers,
Stan H.
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