SOLUTION: m/(m^2-2m+1)+1/(m^2-5m+4)

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Question 25576: m/(m^2-2m+1)+1/(m^2-5m+4)
Answer by stanbon(57977) About Me  (Show Source):
You can put this solution on YOUR website!
Factor the denominators so you can determine the LCD:
m/[(m-1)^2]+1/[(m-1)(m-4)]
The LCD is [(m-1)^2(m-4)]
Rewrite the original problem with a common denominator of LCD:
m(m-4)/LCD + (m-1)/LCD
Now, add the fractions:
[m^2-4m+m-1]/LCD
[m^2-3m-1]/[(m-1)^2(m-4)]
Cheers,
Stan H.