SOLUTION: m/(m^2-2m+1)+1/(m^2-5m+4)

Question 25576: m/(m^2-2m+1)+1/(m^2-5m+4)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Factor the denominators so you can determine the LCD:
m/[(m-1)^2]+1/[(m-1)(m-4)]
The LCD is [(m-1)^2(m-4)]
Rewrite the original problem with a common denominator of LCD:
m(m-4)/LCD + (m-1)/LCD
Now, add the fractions:
[m^2-4m+m-1]/LCD
[m^2-3m-1]/[(m-1)^2(m-4)]
Cheers,
Stan H.
RELATED QUESTIONS
5m+2(m+1)=23 (answered by checkley71)

4(m+2)=3(2m-1) (answered by Fombitz)

(5m^4+m^3-3m^2-m-2) /... (answered by friesr)

2m+4-3m=8(m-1) m=... (answered by ReadingBoosters)

I am confused about this problem I'm not sure if its right. 8/2m+1 - 1/m-2 = 5/2m+1 (answered by sarah_adam)

(3/2m+4)=(1/m+2)-2... (answered by stanbon,Roric)

5m^2 + m - 10... (answered by solver91311)

((m-1)/5)=((2m-3)/3)-2 (answered by stanbon)

m-(2m-3)=1-3m-2 (answered by tommyt3rd)