SOLUTION: Two roots of a polynomial equation with real coefficients are 2+3i and square root of 7. Then find two additional roots. Then find the degree of the polynomial.

Algebra.Com
Question 253818: Two roots of a polynomial equation with real coefficients are 2+3i and square root of 7. Then find two additional roots. Then find the degree of the polynomial.
Answer by drk(1908)   (Show Source): You can put this solution on YOUR website!
FIrst we are given 2 roots:

and
.
The other 2 roots are

and

These are both conjugates.
So, we have a polynomial expressed as

this can be simplified to

and then to

RELATED QUESTIONS

Use the Rational Root Theorem to find all the roots of each equation. 4. x'3 +... (answered by stanbon)
two roots of a polynomial equation are 3-5i and square root of 2. a. find two additional (answered by stanbon)
A polynomial function P(x) with rational coefficients has the given roots. Find two... (answered by mananth)
Please help me on these questions, I've tried for hours and i'm torn. I beg you. Solve (answered by solver91311)
A polynomial equation with rational coefficients has the roots 3 + sqrt6, 2- sqrt5. Find... (answered by KMST)
Three roots of a polynomial equation with real coefficients are 3, 5 – 3i, and –3i. Which (answered by solver91311)
Find a fourth degree polynomial equation with integer coefficients that has the given... (answered by stanbon)
Find a polynomial equation with real coefficients that has the roots of -5,... (answered by ikleyn,Edwin McCravy)
Find the equation of the polynomial with roots (-square root of 3, 0) and (4i, 0) real... (answered by MathLover1)