SOLUTION: find all values of x where the graph y=(2x^3 -3x+4) / (x^2) crosses its oblique asymptote
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Question 252096: find all values of x where the graph y=(2x^3 -3x+4) / (x^2) crosses its oblique asymptote
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
find all values of x where the graph y=(2x^3 -3x+4) / (x^2) crosses its oblique asymptote
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Divide y = 2x^3 - 3x + 4 by x^2 to get:
Quotient: 2x
Remainder: (-3x+4)/x^2
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Oblique asymptote: y = 2x
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Find points of intersection:
2x^3-3x+4 = 2x
2x^3-5x+4 = 0
I graphed it and found one Real solution: x = -1.886796...
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Cheers,
Stan H.
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