SOLUTION: Please solve for x - thankyou {{{2+root(3,13x-11-3x^2) = x}}}

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Question 241072: Please solve for x - thankyou
2%2Broot%283%2C13x-11-3x%5E2%29+=+x

Answer by Edwin McCravy(6938) About Me  (Show Source):
You can put this solution on YOUR website!
2%2Broot%283%2C13x-11-3x%5E2%29+=+x

Isolate the cube root:

root%283%2C13x-11-3x%5E2%29+=+x-2

Raise both sides to the 3rd power (that is, "cube" both sides)

%28root%283%2C13x-11-3x%5E2%29%29%5E3+=+%28x-2%29%5E3

Raising a radical to the same exponent as its index amounts
to removing the radical and the exponent, so we have:

13x-11-3x%5E2+=+%28x-2%29%5E3

But we must multiply the right side out:

13x-11-3x%5E2+=+%28x-2%29%28x-2%29%28x-2%29

13x-11-3x%5E2+=+%28x%5E2-4x%2B4%29%28x-2%29

13x-11-3x%5E2+=+x%5E3-2x%5E2-4x%5E2%2B8x%2B4x-8

13x-11-3x%5E2+=+x%5E3-6x%5E2%2B12x-8

Get 0 on one side:

0=x%5E3-3x%5E2-x%2B3

We like the 0 to be on the right, so we switch sides:

x%5E3-3x%5E2-x%2B3=0

Factor x%5E2 out of the first two terms on the left:

x%5E2%28x-3%29-x%2B3=0

Factor -1 out of the last two terms on the left:

x%5E2%28x-3%29-1%28x-3%29=0

Factor %28x-3%29 out of both terms on the left:

%28x-3%29%28x%5E2-1%29=0

Factor the second parentheses as the difference of sqwuares:

%28x-3%29%28x-1%29%28x%2B1%29=0

Use the zero-factor principle and set each factor = 0:

x-3=0 gives solution x=3

x-1=0 gives solution x=1

x+1=0 gives solution x=-1

The solutions are -1, 1, and 3.  They all check in the original.

(You only need to check radical equations for extraneous solutions
when there is a root with an even index or a denominator containg
a variable.)

Edwin