# SOLUTION: please help me solve this, i cannot get it: the number of bacteria present in a culture after t minutes is given as B=100e^kt. If there are 3367 bacteria present after 8 minutes, f

Algebra ->  Algebra  -> Rational-functions -> SOLUTION: please help me solve this, i cannot get it: the number of bacteria present in a culture after t minutes is given as B=100e^kt. If there are 3367 bacteria present after 8 minutes, f      Log On

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 Question 240895: please help me solve this, i cannot get it: the number of bacteria present in a culture after t minutes is given as B=100e^kt. If there are 3367 bacteria present after 8 minutes, find k.Answer by ankor@dixie-net.com(15650)   (Show Source): You can put this solution on YOUR website! the number of bacteria present in a culture after t minutes is given as B=100e^kt. If there are 3367 bacteria present after 8 minutes, find k. : Replace t with 8 and B with 3367 : 100e^(8k) = 3367 : Divide both sides by 100 e^(8k) = : e^(8k) = 33.67 : Find the nat log of both side, ln(e^8k) = ln(33.67) : 8k*ln(e) = ln(33.67 : nat log of e is 1 8k = 3.5166 : k = k = .4396 : : Check solution on a good calc: enter 100*e^(8*.4396) ~ 3367