SOLUTION: please help me solve this, i cannot get it: the number of bacteria present in a culture after t minutes is given as B=100e^kt. If there are 3367 bacteria present after 8 minutes, f
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Question 240895: please help me solve this, i cannot get it: the number of bacteria present in a culture after t minutes is given as B=100e^kt. If there are 3367 bacteria present after 8 minutes, find k.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
the number of bacteria present in a culture after t minutes is given as B=100e^kt.
If there are 3367 bacteria present after 8 minutes, find k.
:
Replace t with 8 and B with 3367
:
100e^(8k) = 3367
:
Divide both sides by 100
e^(8k) =
:
e^(8k) = 33.67
:
Find the nat log of both side,
ln(e^8k) = ln(33.67)
:
8k*ln(e) = ln(33.67
:
nat log of e is 1
8k = 3.5166
:
k =
k = .4396
:
:
Check solution on a good calc: enter 100*e^(8*.4396) ~ 3367
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