SOLUTION: Solve the system using any algebraic method.
x+2y-6z=23
x+3y+z=4
2x+5y-4z=24
Algebra.Com
Question 237350: Solve the system using any algebraic method.
x+2y-6z=23
x+3y+z=4
2x+5y-4z=24
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve the system using any algebraic method.
x + 2y -6z = 23
x + 3y + z = 4
2x+ 5y -4z = 24
:
Multiply the 1st two equations by -1 to change the signs
-x - 2y +6z = -23
-x - 3y - z = -4
2x + 5y -4z = 24
---------------------addition eliminates x and y, find z
0x + 0y + z = -3
z = -3
:
replace z with -3 in the 1st two equations
x + 2y -6(-3)=23
x + 3y - 3 = 4
:
x + 2y +18 = 23
x + 3y -3 = 4
:
x + 2y = 23 - 18
x + 3y = 4 + 3
:
x + 2y = 5
x + 3y = 7
----------------subtraction eliminates x find y
0x -y = -2
therefore
+y = +2
:
You should be able to find x by yourself now
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