SOLUTION: how do you solve (x^2\16)+ (y^2\16)=1 y=x+3

Question 22588: how do you solve (x^2\16)+ (y^2\16)=1 y=x+3
Answer by stanbon!(97) (Show Source): You can put this solution on YOUR website!
Multiply thru by 16 to get x^2+y^2 = 16
Substitute y=x+3 to get:
x^2 +x^2+6x+9=16
2x^2 + 6x -7 =0
Use the quadratic formula to get

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=92 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.89791576165636, -3.89791576165636. Here's your graph:

Cheers,
Stan H.
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