SOLUTION: How do I do this? (10-5t over 3)multiplied by (12t over t-2)

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Question 22188: How do I do this?
(10-5t over 3)multiplied by (12t over t-2)
Found 2 solutions by eclecticist, rapaljer:
Answer by eclecticist(12) About Me  (Show Source):
You can put this solution on YOUR website!
%28%2810-5%2At%29%2F3%29%2A%2812%2At%2F%28t-2%29%29
First of all, when multiplying fractions, always look to simplify them first. Simplification always takes place between terms in the numerator and terms in the denominator, as a fraction is essentially signifying division. Note that there is a 3 in the denominator of the first fraction, and 12t in the numerator of the second fraction. You can tell that 3 and 12t have a GCF of 3, leaving you with
%28%2810-5%2At%29%2F1%29%2A%284%2At%2F%28t-2%29%29
Next, we can arrange 10 - 5t to -5t + 10. We can factor out -5 to be left with -5(t-2). However, since there is another term t-2 in the denominator of the second fraction, we cancel these two terms out to be left with
%28%28-5%29%2F1%29%2A%2812%2At%2F1%29
The only thing that is left now is multiplication between -5 and 12t, which is -60t

Answer by rapaljer(4667) About Me  (Show Source):
You can put this solution on YOUR website!
There is an error in the solution previously posted. It should have been -5*4t= -20t.

R^2 at SCC